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Message objects implement part of the `mapping' interface, which assumes
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When True and the message is not a multipart, the payload will be
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        Content-Type field.  Anything else will generate a TypeError.

The message will be assumed to be of type text/* encoded with
        charset.input_charset.  It will be converted to charset.output_charset
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cCs\g}|j�}x9|jD].\}}|j�|kr|j|�qqW|sX|S|S(sQReturn a list of all the values for the named field.

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        parameter value contains non-ASCII characters it must be specified as a
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Example:

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        returned.  Since according to RFC 2045, messages always have a default
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RFC 2045 defines a message's default type to be text/plain unless it
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Parameter keys are always compared case insensitively.  The return
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Your application should be prepared to deal with 3-tuple return
        values, and can convert the parameter to a Unicode string like so:

param = msg.get_param('foo')
            if isinstance(param, tuple):
                param = unicode(param[2], param[0] or 'us-ascii')

In any case, the parameter value (either the returned string, or the
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        value will be appended as per RFC 2045.

An alternate header can be specified in the header argument, and all
        parameters will be quoted as necessary unless requote is False.

If charset is specified, the parameter will be encoded according to RFC
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This method replaces the Content-Type header, keeping all the
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        header's quoting as is.  Otherwise, the parameters will be quoted (the
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An alternative header can be specified in the header argument.  When
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Each item will either be a string (the value of the charset parameter
        in the Content-Type header of that part) or the value of the
        'failobj' parameter (defaults to None), if the part does not have a
        main MIME type of "text", or the charset is not defined.

The list will contain one string for each part of the message, plus
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